da leao： It’s time for Arsenal to make a statement this season.
da 888casino： Nearly all of their title rivals have done it so far, in one way or another.
Manchester City of course brushed Manchester United aside in an eye-opening encounter whilst Liverpool beat the Gunners and Chelsea on their own turf. Spurs have gone under the radar but have shown their ready with an unbeaten start whilst United’s battlecry has more been in acquisitions. Regardless of form you don’t get the likes of Zlatan Ibrahimovic and Jose Mourinho in without going close to the title at least.
It’s time for Arsenal, then, to show us what they’ve got against Chelsea.
Their first big clash against Liverpool fell flat, but the Gunners are in much better shape now and here at Football FanCast we think if they follow these three steps, they’ll be well on their way to a victory over one of their fiercest rivals…
Don’t get wound up
Diego Costa will do his very best to tick the Gunners defence off and get them walking. He’s brilliant at doing it too, regardless of what you think of him, so the key for Arsenal is to just brush it off. Gabriel Paulista got involved with him last season and got a red, so to do the same this season would be foolish. The Gunners have to play the game on their own terms.
Get at Chelsea’s defence
Chelsea will still be without John Terry whilst the Blues may also take Branislav Ivanovic out of the side. That leaves the prospect of a back four in which three players are arguably playing in unfamiliar roles. Marcos Alonso comes in, David Luiz is still getting back up to speed and Cesar Azpilicueta is switching sides. It’s a back four that has to be asked questions of from the word go.
Play at pace
Arsenal’s players must have been watching videos this week of how Liverpool dismantled Chelsea and the reccurring theme must have been do everything quickly and sharply. The Blues weren’t given a moment’s rest at Stamford Bridge on Friday night and that’s exactly what Arsenal need to do on Saturday evening if they want to come away with three precious points.